October 07, 2001

Hey Mike... He said he didn't make up theorums very often, but he played around a bit on Mathmatica and came up with this one for you:

If p and q are distinct primes, p > q, and (a,p) = 1, then a^(p-1) is
congruent to 1 (mod pq).

He asked if you solve it for me to let him know how you did it. I sent him the formula you posted last time.

hehe... have fun :)

Tarwyn

J J J

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