_l_o_o_s_e__s_l_u_g_s___.:::?
the slugs . are loose . come see . them leave . trails
October 07, 2001
Hey Mike... He said he didn't make up theorums very often, but he played around a bit on Mathmatica and came up with this one for you:
If p and q are distinct primes, p > q, and (a,p) = 1, then a^(p-1) is
congruent to 1 (mod pq).
He asked if you solve it for me to let him know how you did it. I sent him the formula you posted last time.
hehe... have fun :)
Tarwyn
J J J
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